In a process where 300 J of heat is added to a system and the system does 100 J

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Question: In a process where 300 J of heat is added to a system and the system does 100 J of work, what is the internal energy change?

Options:

Correct Answer: 200 J

Solution:

Using the first law of thermodynamics, ΔU = Q - W = 300 J - 100 J = 200 J.

In a process where 300 J of heat is added to a system and the system does 100 J of work, what is the internal energy change?

In a process where 300 J of heat is added to a system and the system does 100 J of work, what is the internal energy change?

Step 1: Identify the amount of heat added to the system, which is 300 J. This is represented as Q.
Step 2: Identify the amount of work done by the system, which is 100 J. This is represented as W.
Step 3: Use the first law of thermodynamics formula, which is ΔU = Q - W.
Step 4: Substitute the values into the formula: ΔU = 300 J - 100 J.
Step 5: Perform the subtraction: 300 J - 100 J = 200 J.
Step 6: Conclude that the internal energy change (ΔU) is 200 J.

First Law of Thermodynamics – The first law states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) minus the work done by the system (W).