A torque of 12 Nm is applied to a wheel of radius 0.4 m. What is the force appli

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Question: A torque of 12 Nm is applied to a wheel of radius 0.4 m. What is the force applied at the edge of the wheel?

Options:

Correct Answer: 20 N

Solution:

Torque (τ) = r × F, thus F = τ / r = 12 Nm / 0.4 m = 30 N.

A torque of 12 Nm is applied to a wheel of radius 0.4 m. What is the force applied at the edge of the wheel?

A torque of 12 Nm is applied to a wheel of radius 0.4 m. What is the force applied at the edge of the wheel?

Step 1: Understand the formula for torque, which is τ = r × F, where τ is torque, r is the radius, and F is the force.
Step 2: Rearrange the formula to find the force (F). The rearranged formula is F = τ / r.
Step 3: Substitute the given values into the formula. Here, τ = 12 Nm and r = 0.4 m.
Step 4: Calculate the force by dividing the torque by the radius: F = 12 Nm / 0.4 m.
Step 5: Perform the division: 12 divided by 0.4 equals 30.
Step 6: Conclude that the force applied at the edge of the wheel is 30 N.

Torque – Torque is the rotational equivalent of linear force, calculated as the product of the radius and the force applied at that radius.
Force Calculation – The force can be derived from torque by rearranging the formula τ = r × F to solve for F.