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A torque of 12 Nm is applied to a wheel of radius 0.4 m. What is the force appli
A torque of 12 Nm is applied to a wheel of radius 0.4 m. What is the force applied at the edge of the wheel?
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Practice Questions
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Q1
A torque of 12 Nm is applied to a wheel of radius 0.4 m. What is the force applied at the edge of the wheel?
30 N
20 N
15 N
10 N
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Torque (τ) = r × F, thus F = τ / r = 12 Nm / 0.4 m = 30 N.
Questions & Step-by-step Solutions
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Q
Q: A torque of 12 Nm is applied to a wheel of radius 0.4 m. What is the force applied at the edge of the wheel?
Solution:
Torque (τ) = r × F, thus F = τ / r = 12 Nm / 0.4 m = 30 N.
Steps: 6
Show Steps
Step 1: Understand the formula for torque, which is τ = r × F, where τ is torque, r is the radius, and F is the force.
Step 2: Rearrange the formula to find the force (F). The rearranged formula is F = τ / r.
Step 3: Substitute the given values into the formula. Here, τ = 12 Nm and r = 0.4 m.
Step 4: Calculate the force by dividing the torque by the radius: F = 12 Nm / 0.4 m.
Step 5: Perform the division: 12 divided by 0.4 equals 30.
Step 6: Conclude that the force applied at the edge of the wheel is 30 N.
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