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A torque of 10 N·m is applied to a wheel with a moment of inertia of 2 kg·m². Wh
A torque of 10 N·m is applied to a wheel with a moment of inertia of 2 kg·m². What is the angular acceleration of the wheel?
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Practice Questions
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Q1
A torque of 10 N·m is applied to a wheel with a moment of inertia of 2 kg·m². What is the angular acceleration of the wheel?
5 rad/s²
10 rad/s²
2 rad/s²
20 rad/s²
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Using τ = Iα, we have α = τ/I = 10 N·m / 2 kg·m² = 5 rad/s².
Questions & Step-by-step Solutions
1 item
Q
Q: A torque of 10 N·m is applied to a wheel with a moment of inertia of 2 kg·m². What is the angular acceleration of the wheel?
Solution:
Using τ = Iα, we have α = τ/I = 10 N·m / 2 kg·m² = 5 rad/s².
Steps: 5
Show Steps
Step 1: Understand the formula for angular acceleration, which is α = τ / I.
Step 2: Identify the values given in the question: torque (τ) is 10 N·m and moment of inertia (I) is 2 kg·m².
Step 3: Substitute the values into the formula: α = 10 N·m / 2 kg·m².
Step 4: Perform the division: 10 divided by 2 equals 5.
Step 5: Conclude that the angular acceleration (α) is 5 rad/s².
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