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If the magnetic field strength is doubled, what happens to the force on a charge

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Question: If the magnetic field strength is doubled, what happens to the force on a charged particle moving perpendicular to the field?

Options:

  1. It doubles
  2. It halves
  3. It remains the same
  4. It quadruples

Correct Answer: It doubles

Solution:

The force on a charged particle is directly proportional to the magnetic field strength, so if the magnetic field strength is doubled, the force also doubles.

If the magnetic field strength is doubled, what happens to the force on a charge

Practice Questions

Q1
If the magnetic field strength is doubled, what happens to the force on a charged particle moving perpendicular to the field?
  1. It doubles
  2. It halves
  3. It remains the same
  4. It quadruples

Questions & Step-by-Step Solutions

If the magnetic field strength is doubled, what happens to the force on a charged particle moving perpendicular to the field?
  • Step 1: Understand that a charged particle moving in a magnetic field experiences a force.
  • Step 2: Know that the force on the charged particle is calculated using the formula F = q * v * B, where F is the force, q is the charge, v is the velocity, and B is the magnetic field strength.
  • Step 3: Recognize that in this formula, the force (F) is directly proportional to the magnetic field strength (B).
  • Step 4: If the magnetic field strength (B) is doubled, it means we replace B with 2B in the formula.
  • Step 5: This means the new force (F') will be F' = q * v * (2B) = 2 * (q * v * B) = 2F.
  • Step 6: Conclude that if the magnetic field strength is doubled, the force on the charged particle also doubles.
  • Magnetic Force on Charged Particles – The force experienced by a charged particle moving in a magnetic field is given by the equation F = qvB sin(θ), where F is the force, q is the charge, v is the velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field. When the particle moves perpendicular to the field, sin(θ) = 1.
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