A cyclist is negotiating a circular track of radius 30 m. If the cyclist's speed

Practice Questions

Q1
A cyclist is negotiating a circular track of radius 30 m. If the cyclist's speed is 15 m/s, what is the net force acting on the cyclist towards the center of the track?
  1. 50 N
  2. 75 N
  3. 100 N
  4. 125 N

Questions & Step-by-Step Solutions

A cyclist is negotiating a circular track of radius 30 m. If the cyclist's speed is 15 m/s, what is the net force acting on the cyclist towards the center of the track?
  • Step 1: Identify the formula for centripetal force, which is F_c = mv²/r.
  • Step 2: Determine the values needed for the formula. We have the speed (v = 15 m/s) and the radius (r = 30 m).
  • Step 3: Assume a mass for the cyclist. In this case, we will use m = 100 kg.
  • Step 4: Calculate v² (the speed squared). So, v² = (15 m/s)² = 225 m²/s².
  • Step 5: Substitute the values into the centripetal force formula: F_c = (100 kg)(225 m²/s²) / (30 m).
  • Step 6: Perform the multiplication: (100 kg)(225 m²/s²) = 22500 kg·m²/s².
  • Step 7: Divide the result by the radius: 22500 kg·m²/s² / 30 m = 750 kg·m/s².
  • Step 8: Since 1 kg·m/s² is equal to 1 Newton (N), the net force acting on the cyclist towards the center of the track is 750 N.
  • Centripetal Force – The net force required to keep an object moving in a circular path, directed towards the center of the circle.
  • Kinematics – Understanding the relationship between speed, radius, and the forces acting on an object in circular motion.
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