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An object is thrown vertically upward with a speed of 20 m/s. How high will it r
An object is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?
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Q1
An object is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?
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Maximum height (H) = (u²)/(2g) = (20²)/(2*9.8) ≈ 20.4 m.
Questions & Step-by-step Solutions
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Q
Q: An object is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?
Solution:
Maximum height (H) = (u²)/(2g) = (20²)/(2*9.8) ≈ 20.4 m.
Steps: 8
Show Steps
Step 1: Identify the initial speed (u) of the object. In this case, u = 20 m/s.
Step 2: Identify the acceleration due to gravity (g). This is approximately 9.8 m/s².
Step 3: Use the formula for maximum height (H) when an object is thrown upwards: H = (u²) / (2g).
Step 4: Substitute the values into the formula: H = (20 m/s)² / (2 * 9.8 m/s²).
Step 5: Calculate (20 m/s)², which equals 400 m²/s².
Step 6: Calculate 2 * 9.8 m/s², which equals 19.6 m/s².
Step 7: Divide 400 m²/s² by 19.6 m/s² to find H: H ≈ 20.4 m.
Step 8: Conclude that the maximum height the object will rise before coming to rest is approximately 20.4 meters.
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