A stone is dropped from a height of 45 m. How far will it have fallen after 2 seconds?
Practice Questions
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Q1
A stone is dropped from a height of 45 m. How far will it have fallen after 2 seconds?
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Distance fallen (s) = (1/2)gt² = (1/2)(9.8)(2²) = 19.6 m.
Questions & Step-by-step Solutions
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Q
Q: A stone is dropped from a height of 45 m. How far will it have fallen after 2 seconds?
Solution: Distance fallen (s) = (1/2)gt² = (1/2)(9.8)(2²) = 19.6 m.
Steps: 7
Step 1: Understand that the stone is dropped from a height of 45 m.
Step 2: Know that the formula to calculate the distance fallen is s = (1/2)gt², where g is the acceleration due to gravity (approximately 9.8 m/s²) and t is the time in seconds.
Step 3: Substitute the values into the formula. Here, g = 9.8 m/s² and t = 2 seconds.
Step 4: Calculate t² (2 seconds squared). This is 2 * 2 = 4.
Step 5: Now, multiply g (9.8) by t² (4). This gives you 9.8 * 4 = 39.2.
Step 6: Multiply this result by (1/2). So, (1/2) * 39.2 = 19.6.
Step 7: The distance fallen after 2 seconds is 19.6 meters.