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A stone is thrown vertically upwards with a speed of 20 m/s. How long will it ta
A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)
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Q1
A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)
1 s
2 s
3 s
4 s
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Using the formula: v = u - gt. At maximum height, v = 0. So, 0 = 20 - 10t. Solving gives t = 2 s.
Questions & Step-by-step Solutions
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Q
Q: A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)
Solution:
Using the formula: v = u - gt. At maximum height, v = 0. So, 0 = 20 - 10t. Solving gives t = 2 s.
Steps: 7
Show Steps
Step 1: Identify the initial speed (u) of the stone, which is 20 m/s.
Step 2: Recognize that at the maximum height, the final speed (v) of the stone will be 0 m/s.
Step 3: Use the formula v = u - gt, where g is the acceleration due to gravity (10 m/s²) and t is the time in seconds.
Step 4: Substitute the known values into the formula: 0 = 20 - 10t.
Step 5: Rearrange the equation to solve for t: 10t = 20.
Step 6: Divide both sides by 10 to find t: t = 20 / 10.
Step 7: Calculate the result: t = 2 seconds.
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