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A charged capacitor has a potential difference of 12 V across its plates. If the
A charged capacitor has a potential difference of 12 V across its plates. If the capacitance is 4 µF, what is the charge stored in the capacitor?
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Practice Questions
1 question
Q1
A charged capacitor has a potential difference of 12 V across its plates. If the capacitance is 4 µF, what is the charge stored in the capacitor?
48 µC
12 µC
3 µC
24 µC
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Charge Q = C × V = 4 µF × 12 V = 48 µC.
Questions & Step-by-step Solutions
1 item
Q
Q: A charged capacitor has a potential difference of 12 V across its plates. If the capacitance is 4 µF, what is the charge stored in the capacitor?
Solution:
Charge Q = C × V = 4 µF × 12 V = 48 µC.
Steps: 6
Show Steps
Step 1: Understand the formula for charge stored in a capacitor, which is Q = C × V.
Step 2: Identify the values given in the question: capacitance (C) is 4 µF and potential difference (V) is 12 V.
Step 3: Convert the capacitance from microfarads (µF) to farads (F) if necessary. 4 µF = 4 × 10^-6 F.
Step 4: Plug the values into the formula: Q = 4 µF × 12 V.
Step 5: Calculate the charge: Q = 4 × 10^-6 F × 12 V = 48 × 10^-6 C.
Step 6: Convert the charge to microcoulombs (µC): 48 × 10^-6 C = 48 µC.
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