A charged capacitor has a potential difference of 12 V across its plates. If the

A charged capacitor has a potential difference of 12 V across its plates. If the capacitance is 4 µF, what is the charge stored in the capacitor?

A charged capacitor has a potential difference of 12 V across its plates. If the capacitance is 4 µF, what is the charge stored in the capacitor?

Step 1: Understand the formula for charge stored in a capacitor, which is Q = C × V.
Step 2: Identify the values given in the question: capacitance (C) is 4 µF and potential difference (V) is 12 V.
Step 3: Convert the capacitance from microfarads (µF) to farads (F) if necessary. 4 µF = 4 × 10^-6 F.
Step 4: Plug the values into the formula: Q = 4 µF × 12 V.
Step 5: Calculate the charge: Q = 4 × 10^-6 F × 12 V = 48 × 10^-6 C.
Step 6: Convert the charge to microcoulombs (µC): 48 × 10^-6 C = 48 µC.

Capacitance and Charge Relationship – The relationship between charge (Q), capacitance (C), and voltage (V) is given by the formula Q = C × V.