Question: A charged capacitor has a potential difference of 12 V across its plates. If the capacitance is 4 µF, what is the charge stored in the capacitor?
Options:
48 µC
12 µC
3 µC
24 µC
Correct Answer: 48 µC
Solution:
Charge Q = C × V = 4 µF × 12 V = 48 µC.
A charged capacitor has a potential difference of 12 V across its plates. If the
Practice Questions
Q1
A charged capacitor has a potential difference of 12 V across its plates. If the capacitance is 4 µF, what is the charge stored in the capacitor?
48 µC
12 µC
3 µC
24 µC
Questions & Step-by-Step Solutions
A charged capacitor has a potential difference of 12 V across its plates. If the capacitance is 4 µF, what is the charge stored in the capacitor?
Step 1: Understand the formula for charge stored in a capacitor, which is Q = C × V.
Step 2: Identify the values given in the question: capacitance (C) is 4 µF and potential difference (V) is 12 V.
Step 3: Convert the capacitance from microfarads (µF) to farads (F) if necessary. 4 µF = 4 × 10^-6 F.
Step 4: Plug the values into the formula: Q = 4 µF × 12 V.
Step 5: Calculate the charge: Q = 4 × 10^-6 F × 12 V = 48 × 10^-6 C.
Step 6: Convert the charge to microcoulombs (µC): 48 × 10^-6 C = 48 µC.
Capacitance and Charge Relationship – The relationship between charge (Q), capacitance (C), and voltage (V) is given by the formula Q = C × V.
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