What is the electric field due to a point charge of +4μC at a distance of 0.2m?
Practice Questions
Q1
What is the electric field due to a point charge of +4μC at a distance of 0.2m?
4500 N/C
9000 N/C
18000 N/C
36000 N/C
Questions & Step-by-Step Solutions
What is the electric field due to a point charge of +4μC at a distance of 0.2m?
Step 1: Identify the formula for electric field (E) due to a point charge: E = k * |q| / r^2.
Step 2: Identify the values needed for the formula: k (Coulomb's constant) = 9 × 10^9 N m²/C², q (charge) = +4μC = 4 × 10^-6 C, and r (distance) = 0.2 m.
Step 3: Substitute the values into the formula: E = (9 × 10^9) * (4 × 10^-6) / (0.2)^2.
Step 4: Calculate (0.2)^2, which is 0.04.
Step 5: Now calculate E: E = (9 × 10^9) * (4 × 10^-6) / 0.04.
Step 6: Multiply (9 × 10^9) by (4 × 10^-6) to get 36,000.
