If R1 = 10Ω, R2 = 15Ω, R3 = 5Ω, what should R4 be for the Wheatstone bridge to b

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Question: If R1 = 10Ω, R2 = 15Ω, R3 = 5Ω, what should R4 be for the Wheatstone bridge to be balanced?

Options:

Correct Answer: 12.5Ω

Solution:

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (15 * 5) / 10 = 7.5Ω.

If R1 = 10Ω, R2 = 15Ω, R3 = 5Ω, what should R4 be for the Wheatstone bridge to be balanced?

If R1 = 10Ω, R2 = 15Ω, R3 = 5Ω, what should R4 be for the Wheatstone bridge to be balanced?

Step 1: Identify the resistances given in the problem: R1 = 10Ω, R2 = 15Ω, R3 = 5Ω.
Step 2: Write down the balance condition for a Wheatstone bridge, which is R1/R2 = R3/R4.
Step 3: Rearrange the balance condition to solve for R4: R4 = (R2 * R3) / R1.
Step 4: Substitute the values of R2, R3, and R1 into the equation: R4 = (15 * 5) / 10.
Step 5: Calculate the multiplication: 15 * 5 = 75.
Step 6: Divide the result by R1: 75 / 10 = 7.5.
Step 7: Conclude that R4 should be 7.5Ω for the Wheatstone bridge to be balanced.

Wheatstone Bridge Balance Condition – The Wheatstone bridge is balanced when the ratio of the resistances in one leg equals the ratio in the other leg, expressed as R1/R2 = R3/R4.
Ohm's Law – Understanding the relationship between voltage, current, and resistance, which is fundamental in analyzing circuits.