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In a potentiometer experiment, if the balance point is found at 4 m with a 12 V

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Question: In a potentiometer experiment, if the balance point is found at 4 m with a 12 V battery, what is the voltage across a 2 m length of the same wire?

Options:

  1. 6 V
  2. 3 V
  3. 4 V
  4. 2 V

Correct Answer: 3 V

Solution: 

Using the potential gradient, the voltage across 2 m is (12 V / 4 m) * 2 m = 6 V.

In a potentiometer experiment, if the balance point is found at 4 m with a 12 V

Practice Questions

Q1
In a potentiometer experiment, if the balance point is found at 4 m with a 12 V battery, what is the voltage across a 2 m length of the same wire?
  1. 6 V
  2. 3 V
  3. 4 V
  4. 2 V

Questions & Step-by-Step Solutions

In a potentiometer experiment, if the balance point is found at 4 m with a 12 V battery, what is the voltage across a 2 m length of the same wire?
  • Step 1: Understand that a potentiometer measures voltage using a wire with a uniform potential gradient.
  • Step 2: Identify the total voltage provided by the battery, which is 12 V.
  • Step 3: Note the length of the wire where the balance point is found, which is 4 m.
  • Step 4: Calculate the potential gradient (voltage per meter) by dividing the total voltage by the length of the wire: 12 V / 4 m = 3 V/m.
  • Step 5: Determine the length of the wire for which you want to find the voltage, which is 2 m.
  • Step 6: Calculate the voltage across the 2 m length using the potential gradient: 3 V/m * 2 m = 6 V.
  • Potential Gradient – The potential gradient in a potentiometer is the voltage per unit length of the wire, which allows for the calculation of voltage across different lengths of the wire.
  • Proportionality – Understanding that the voltage across a segment of wire is directly proportional to its length when the potential gradient is constant.
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