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In a circuit with a 9V battery and three resistors in series (2Ω, 3Ω, and 5Ω), w
In a circuit with a 9V battery and three resistors in series (2Ω, 3Ω, and 5Ω), what is the total resistance?
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Practice Questions
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Q1
In a circuit with a 9V battery and three resistors in series (2Ω, 3Ω, and 5Ω), what is the total resistance?
5Ω
8Ω
10Ω
15Ω
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Total resistance R = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω.
Questions & Step-by-step Solutions
1 item
Q
Q: In a circuit with a 9V battery and three resistors in series (2Ω, 3Ω, and 5Ω), what is the total resistance?
Solution:
Total resistance R = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω.
Steps: 6
Show Steps
Step 1: Identify the resistors in the circuit. We have three resistors: 2Ω, 3Ω, and 5Ω.
Step 2: Understand that when resistors are in series, you add their resistances together.
Step 3: Write down the formula for total resistance in series: Total resistance R = R1 + R2 + R3.
Step 4: Substitute the values of the resistors into the formula: R = 2Ω + 3Ω + 5Ω.
Step 5: Perform the addition: 2 + 3 = 5, then 5 + 5 = 10.
Step 6: Conclude that the total resistance is 10Ω.
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