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What is the voltage drop across a 5Ω resistor carrying a current of 3A?
What is the voltage drop across a 5Ω resistor carrying a current of 3A?
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Practice Questions
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Q1
What is the voltage drop across a 5Ω resistor carrying a current of 3A?
5V
10V
15V
20V
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Using Ohm's law, V = I * R = 3A * 5Ω = 15V.
Questions & Step-by-step Solutions
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Q
Q: What is the voltage drop across a 5Ω resistor carrying a current of 3A?
Solution:
Using Ohm's law, V = I * R = 3A * 5Ω = 15V.
Steps: 6
Show Steps
Step 1: Identify the values given in the problem. We have a resistor with a resistance of 5 ohms (Ω) and a current of 3 amperes (A).
Step 2: Recall Ohm's law, which states that voltage (V) is equal to current (I) multiplied by resistance (R). The formula is V = I * R.
Step 3: Substitute the values into the formula. Here, I = 3A and R = 5Ω.
Step 4: Calculate the voltage drop by multiplying the current by the resistance: V = 3A * 5Ω.
Step 5: Perform the multiplication: 3 * 5 = 15.
Step 6: Conclude that the voltage drop across the resistor is 15 volts (V).
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