What is the voltage drop across a 5Ω resistor carrying a current of 3A?

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Question: What is the voltage drop across a 5Ω resistor carrying a current of 3A?

Options:

Correct Answer: 15V

Solution:

Using Ohm\'s law, V = I * R = 3A * 5Ω = 15V.

What is the voltage drop across a 5Ω resistor carrying a current of 3A?

What is the voltage drop across a 5Ω resistor carrying a current of 3A?

Step 1: Identify the values given in the problem. We have a resistor with a resistance of 5 ohms (Ω) and a current of 3 amperes (A).
Step 2: Recall Ohm's law, which states that voltage (V) is equal to current (I) multiplied by resistance (R). The formula is V = I * R.
Step 3: Substitute the values into the formula. Here, I = 3A and R = 5Ω.
Step 4: Calculate the voltage drop by multiplying the current by the resistance: V = 3A * 5Ω.
Step 5: Perform the multiplication: 3 * 5 = 15.
Step 6: Conclude that the voltage drop across the resistor is 15 volts (V).

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