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In a circuit with a 24V battery and two 12Ω resistors in series, what is the cur

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Question: In a circuit with a 24V battery and two 12Ω resistors in series, what is the current flowing through the circuit?

Options:

  1. 1A
  2. 2A
  3. 3A
  4. 4A

Correct Answer: 2A

Solution:

Total resistance R_total = 12Ω + 12Ω = 24Ω. Current I = V/R_total = 24V / 24Ω = 1A.

In a circuit with a 24V battery and two 12Ω resistors in series, what is the cur

Practice Questions

Q1
In a circuit with a 24V battery and two 12Ω resistors in series, what is the current flowing through the circuit?
  1. 1A
  2. 2A
  3. 3A
  4. 4A

Questions & Step-by-Step Solutions

In a circuit with a 24V battery and two 12Ω resistors in series, what is the current flowing through the circuit?
  • Step 1: Identify the voltage of the battery, which is 24V.
  • Step 2: Identify the resistance of each resistor, which is 12Ω.
  • Step 3: Since the resistors are in series, add their resistances together: 12Ω + 12Ω = 24Ω.
  • Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
  • Step 5: Substitute the values into the formula: I = 24V / 24Ω.
  • Step 6: Calculate the current: I = 1A.
  • Ohm's Law – Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor.
  • Series Circuits – In a series circuit, the total resistance is the sum of the individual resistances, and the same current flows through all components.
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