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Find the distance from the point (3, 4) to the line 2x + 3y - 6 = 0.
Find the distance from the point (3, 4) to the line 2x + 3y - 6 = 0.
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Find the distance from the point (3, 4) to the line 2x + 3y - 6 = 0.
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Distance = |Ax1 + By1 + C| / sqrt(A^2 + B^2) = |2*3 + 3*4 - 6| / sqrt(2^2 + 3^2) = |6 + 12 - 6| / sqrt(13) = 12 / sqrt(13).
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Q: Find the distance from the point (3, 4) to the line 2x + 3y - 6 = 0.
Solution:
Distance = |Ax1 + By1 + C| / sqrt(A^2 + B^2) = |2*3 + 3*4 - 6| / sqrt(2^2 + 3^2) = |6 + 12 - 6| / sqrt(13) = 12 / sqrt(13).
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