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If f(x) = { x^2, x < 0; kx + 1, x >= 0 } is differentiable at x = 0, what
If f(x) = { x^2, x < 0; kx + 1, x >= 0 } is differentiable at x = 0, what is k?
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If f(x) = { x^2, x < 0; kx + 1, x >= 0 } is differentiable at x = 0, what is k?
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Setting the derivatives equal at x = 0 gives k = 0.
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Q: If f(x) = { x^2, x < 0; kx + 1, x >= 0 } is differentiable at x = 0, what is k?
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Setting the derivatives equal at x = 0 gives k = 0.
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