The function f(x) = x^3 - 3x + 2 is differentiable everywhere. What is f'(1)?

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The function f(x) = x^3 - 3x + 2 is differentiable everywhere. What is f'(1)?
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Q: The function f(x) = x^3 - 3x + 2 is differentiable everywhere. What is f'(1)?
Solution: f'(x) = 3x^2 - 3, thus f'(1) = 0.
Steps: 0

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