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What is the value of the integral ∫(0 to 1) (3x^2 + 2)dx?
Practice Questions
Q1
What is the value of the integral ∫(0 to 1) (3x^2 + 2)dx?
5/3
2
1
4/3
Questions & Step-by-Step Solutions
What is the value of the integral ∫(0 to 1) (3x^2 + 2)dx?
Steps
Concepts
Step 1: Identify the integral you need to solve: ∫(0 to 1) (3x^2 + 2)dx.
Step 2: Find the antiderivative of the function 3x^2 + 2. The antiderivative is x^3 + 2x.
Step 3: Evaluate the antiderivative at the upper limit (1): (1^3 + 2*1) = (1 + 2) = 3.
Step 4: Evaluate the antiderivative at the lower limit (0): (0^3 + 2*0) = (0 + 0) = 0.
Step 5: Subtract the value at the lower limit from the value at the upper limit: 3 - 0 = 3.
Step 6: The value of the integral is 3.
No concepts available.
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