For a reaction with ΔH = 100 kJ/mol and ΔS = 200 J/mol·K, at what temperature wi

Practice Questions

Q1
For a reaction with ΔH = 100 kJ/mol and ΔS = 200 J/mol·K, at what temperature will the reaction become spontaneous?
  1. 500 K
  2. 250 K
  3. 200 K
  4. 100 K

Questions & Step-by-Step Solutions

For a reaction with ΔH = 100 kJ/mol and ΔS = 200 J/mol·K, at what temperature will the reaction become spontaneous?
  • Step 1: Understand that for a reaction to be spontaneous, the change in Gibbs free energy (ΔG) must be less than or equal to zero (ΔG ≤ 0).
  • Step 2: Use the formula for Gibbs free energy: ΔG = ΔH - TΔS, where ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy.
  • Step 3: Set ΔG to 0 to find the temperature at which the reaction becomes spontaneous: 0 = ΔH - TΔS.
  • Step 4: Rearrange the equation to solve for T: T = ΔH / ΔS.
  • Step 5: Convert ΔH from kJ to J because ΔS is in J: ΔH = 100 kJ/mol = 100,000 J/mol.
  • Step 6: Substitute the values into the equation: T = 100,000 J/mol / 200 J/mol·K.
  • Step 7: Calculate the temperature: T = 500 K.
  • Gibbs Free Energy – Understanding the relationship between enthalpy (ΔH), entropy (ΔS), and temperature (T) in determining spontaneity of a reaction.
  • Thermodynamic Equations – Application of the equation ΔG = ΔH - TΔS to find the temperature at which a reaction becomes spontaneous.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely