If 15 grams of HCl is dissolved in 500 mL of solution, what is the molarity of the solution? (Molar mass of HCl = 36.5 g/mol)

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Q: If 15 grams of HCl is dissolved in 500 mL of solution, what is the molarity of the solution? (Molar mass of HCl = 36.5 g/mol)

Solution: Moles of HCl = 15 g / 36.5 g/mol = 0.41096 moles. Molarity = 0.41096 moles / 0.5 L = 0.82192 M.

Steps: 9

Step 1: Identify the mass of HCl given, which is 15 grams.
Step 2: Identify the molar mass of HCl, which is 36.5 g/mol.
Step 3: Calculate the number of moles of HCl using the formula: Moles = Mass / Molar Mass.
Step 4: Substitute the values: Moles of HCl = 15 g / 36.5 g/mol.
Step 5: Perform the calculation: Moles of HCl = 0.41096 moles.
Step 6: Identify the volume of the solution, which is 500 mL. Convert this to liters: 500 mL = 0.5 L.
Step 7: Calculate the molarity using the formula: Molarity = Moles of solute / Volume of solution in liters.
Step 8: Substitute the values: Molarity = 0.41096 moles / 0.5 L.
Step 9: Perform the calculation: Molarity = 0.82192 M.