What is the molarity of a solution if 10 grams of CaCl2 is dissolved in 250 mL o

₹0.0

Question: What is the molarity of a solution if 10 grams of CaCl2 is dissolved in 250 mL of solution? (Molar mass of CaCl2 = 110 g/mol)

Options:

Correct Answer: 0.5 M

Solution:

Moles of CaCl2 = 10 g / 110 g/mol = 0.0909 moles. Molarity = 0.0909 moles / 0.25 L = 0.3636 M.

What is the molarity of a solution if 10 grams of CaCl2 is dissolved in 250 mL of solution? (Molar mass of CaCl2 = 110 g/mol)

What is the molarity of a solution if 10 grams of CaCl2 is dissolved in 250 mL of solution? (Molar mass of CaCl2 = 110 g/mol)

Step 1: Find the molar mass of CaCl2, which is given as 110 g/mol.
Step 2: Calculate the number of moles of CaCl2 by dividing the mass (10 grams) by the molar mass (110 g/mol). This gives you 10 g / 110 g/mol = 0.0909 moles.
Step 3: Convert the volume of the solution from milliliters to liters. Since 250 mL is equal to 0.25 L, we use this value for our calculation.
Step 4: Calculate the molarity of the solution by dividing the number of moles (0.0909 moles) by the volume in liters (0.25 L). This gives you 0.0909 moles / 0.25 L = 0.3636 M.

No concepts available.