If 20 grams of glucose (C6H12O6) is dissolved in 200 mL of solution, what is the

If 20 grams of glucose (C6H12O6) is dissolved in 200 mL of solution, what is the mass percent concentration? (Molar mass of glucose = 180 g/mol)

If 20 grams of glucose (C6H12O6) is dissolved in 200 mL of solution, what is the mass percent concentration? (Molar mass of glucose = 180 g/mol)

Step 1: Identify the mass of the solute (glucose) which is 20 grams.
Step 2: Identify the volume of the solution which is 200 mL.
Step 3: Convert the volume of the solution to mass. Since the density of water is approximately 1 g/mL, 200 mL of solution has a mass of about 200 grams.
Step 4: Calculate the total mass of the solution by adding the mass of the solute (20 g) to the mass of the solvent (200 g). Total mass = 20 g + 200 g = 220 g.
Step 5: Use the mass percent formula: Mass percent = (mass of solute / total mass of solution) x 100.
Step 6: Substitute the values into the formula: Mass percent = (20 g / 220 g) x 100.
Step 7: Calculate the mass percent: (20 / 220) x 100 = 9.09%.
Step 8: Round the result to the nearest whole number if necessary, which gives approximately 10%.

Mass Percent Concentration – The mass percent concentration is calculated by taking the mass of the solute divided by the total mass of the solution, multiplied by 100.
Total Mass of Solution – The total mass of the solution includes both the mass of the solute and the mass of the solvent.