If 20 grams of glucose (C6H12O6) is dissolved in 200 mL of solution, what is the mass percent concentration? (Molar mass of glucose = 180 g/mol)
Practice Questions
1 question
Q1
If 20 grams of glucose (C6H12O6) is dissolved in 200 mL of solution, what is the mass percent concentration? (Molar mass of glucose = 180 g/mol)
10%
5%
20%
15%
Mass percent = (mass of solute / total mass of solution) x 100 = (20 g / (20 g + 200 g)) x 100 = 10%.
Questions & Step-by-step Solutions
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Q
Q: If 20 grams of glucose (C6H12O6) is dissolved in 200 mL of solution, what is the mass percent concentration? (Molar mass of glucose = 180 g/mol)
Solution: Mass percent = (mass of solute / total mass of solution) x 100 = (20 g / (20 g + 200 g)) x 100 = 10%.
Steps: 8
Step 1: Identify the mass of the solute (glucose) which is 20 grams.
Step 2: Identify the volume of the solution which is 200 mL.
Step 3: Convert the volume of the solution to mass. Since the density of water is approximately 1 g/mL, 200 mL of solution has a mass of about 200 grams.
Step 4: Calculate the total mass of the solution by adding the mass of the solute (20 g) to the mass of the solvent (200 g). Total mass = 20 g + 200 g = 220 g.
Step 5: Use the mass percent formula: Mass percent = (mass of solute / total mass of solution) x 100.
Step 6: Substitute the values into the formula: Mass percent = (20 g / 220 g) x 100.
Step 7: Calculate the mass percent: (20 / 220) x 100 = 9.09%.
Step 8: Round the result to the nearest whole number if necessary, which gives approximately 10%.
