What is the freezing point depression of a solution if 0.5 mol of a non-volatile solute is dissolved in 1 kg of water? (Kf for water = 1.86 °C kg/mol)
Practice Questions
1 question
Q1
What is the freezing point depression of a solution if 0.5 mol of a non-volatile solute is dissolved in 1 kg of water? (Kf for water = 1.86 °C kg/mol)
0.93 °C
1.86 °C
3.72 °C
0.5 °C
Freezing point depression = Kf * molality = 1.86 * 0.5 = 0.93 °C.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the freezing point depression of a solution if 0.5 mol of a non-volatile solute is dissolved in 1 kg of water? (Kf for water = 1.86 °C kg/mol)
Solution: Freezing point depression = Kf * molality = 1.86 * 0.5 = 0.93 °C.
Steps: 6
Step 1: Identify the formula for freezing point depression, which is: Freezing point depression = Kf * molality.
Step 2: Determine the value of Kf for water, which is given as 1.86 °C kg/mol.
Step 3: Calculate the molality of the solution. Since we have 0.5 mol of solute and 1 kg of water, the molality is 0.5 mol/kg.
Step 4: Plug the values into the formula: Freezing point depression = 1.86 °C kg/mol * 0.5 mol/kg.
Step 5: Perform the multiplication: 1.86 * 0.5 = 0.93 °C.
Step 6: Conclude that the freezing point depression of the solution is 0.93 °C.
