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What is the vapor pressure of a solution containing 1 mole of a non-volatile sol

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Question: What is the vapor pressure of a solution containing 1 mole of a non-volatile solute in 9 moles of solvent, if the vapor pressure of the pure solvent is 100 mmHg?

Options:

  1. 90 mmHg
  2. 100 mmHg
  3. 10 mmHg
  4. 80 mmHg

Correct Answer: 90 mmHg

Solution: 

Using Raoult\'s law, P_solution = X_solvent * P°_solvent = (9/10) * 100 mmHg = 90 mmHg.

What is the vapor pressure of a solution containing 1 mole of a non-volatile sol

Practice Questions

Q1
What is the vapor pressure of a solution containing 1 mole of a non-volatile solute in 9 moles of solvent, if the vapor pressure of the pure solvent is 100 mmHg?
  1. 90 mmHg
  2. 100 mmHg
  3. 10 mmHg
  4. 80 mmHg

Questions & Step-by-Step Solutions

What is the vapor pressure of a solution containing 1 mole of a non-volatile solute in 9 moles of solvent, if the vapor pressure of the pure solvent is 100 mmHg?
  • Step 1: Identify the total number of moles in the solution. You have 1 mole of solute and 9 moles of solvent, so total moles = 1 + 9 = 10 moles.
  • Step 2: Calculate the mole fraction of the solvent (X_solvent). This is done by dividing the moles of solvent by the total moles: X_solvent = moles of solvent / total moles = 9 / 10.
  • Step 3: Identify the vapor pressure of the pure solvent (P°_solvent), which is given as 100 mmHg.
  • Step 4: Use Raoult's law to find the vapor pressure of the solution (P_solution). According to Raoult's law, P_solution = X_solvent * P°_solvent.
  • Step 5: Substitute the values into the equation: P_solution = (9/10) * 100 mmHg.
  • Step 6: Calculate the result: P_solution = 90 mmHg.
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