What is the bond order of the ion O2-?

1 question

1 item

Q: What is the bond order of the ion O2-?

Solution: O2- has a bond order of 1, calculated as (10 bonding electrons - 7 antibonding electrons)/2 = 1.

Steps: 10

Step 1: Understand that bond order is a way to measure the strength and stability of a bond between two atoms.
Step 2: Know that in molecular orbital theory, electrons are placed in bonding and antibonding orbitals.
Step 3: For the ion O2-, we need to determine the number of bonding and antibonding electrons.
Step 4: Oxygen (O) has 8 electrons. O2 has a total of 16 electrons (8 from each O). O2- has 1 extra electron, making it 17 electrons.
Step 5: Fill the molecular orbitals with these 17 electrons according to the rules of molecular orbital theory.
Step 6: The first 10 electrons will fill the bonding orbitals, and the next 7 will fill the antibonding orbitals.
Step 7: Count the bonding electrons: there are 10 bonding electrons.
Step 8: Count the antibonding electrons: there are 7 antibonding electrons.
Step 9: Use the bond order formula: Bond Order = (Number of Bonding Electrons - Number of Antibonding Electrons) / 2.
Step 10: Plug in the numbers: Bond Order = (10 - 7) / 2 = 3 / 2 = 1.