O2- has a bond order of 1, calculated as (10 bonding electrons - 7 antibonding electrons)/2 = 1.
What is the bond order of the ion O2-?
Practice Questions
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What is the bond order of the ion O2-?
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Questions & Step-by-Step Solutions
What is the bond order of the ion O2-?
Step 1: Understand that bond order is a way to measure the strength and stability of a bond between two atoms.
Step 2: Know that in molecular orbital theory, electrons are placed in bonding and antibonding orbitals.
Step 3: For the ion O2-, we need to determine the number of bonding and antibonding electrons.
Step 4: Oxygen (O) has 8 electrons. O2 has a total of 16 electrons (8 from each O). O2- has 1 extra electron, making it 17 electrons.
Step 5: Fill the molecular orbitals with these 17 electrons according to the rules of molecular orbital theory.
Step 6: The first 10 electrons will fill the bonding orbitals, and the next 7 will fill the antibonding orbitals.
Step 7: Count the bonding electrons: there are 10 bonding electrons.
Step 8: Count the antibonding electrons: there are 7 antibonding electrons.
Step 9: Use the bond order formula: Bond Order = (Number of Bonding Electrons - Number of Antibonding Electrons) / 2.
Step 10: Plug in the numbers: Bond Order = (10 - 7) / 2 = 3 / 2 = 1.
Bond Order – Bond order is a measure of the number of chemical bonds between a pair of atoms, calculated as the difference between the number of bonding and antibonding electrons divided by two.
Molecular Orbital Theory – This theory explains the behavior of electrons in molecules, including how they occupy molecular orbitals that can be bonding or antibonding.
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