In a hydraulic lift, if the input power is 500 W and the efficiency is 80%, what

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Question: In a hydraulic lift, if the input power is 500 W and the efficiency is 80%, what is the output power?

Options:

Correct Answer: 400 W

Solution:

Output power can be calculated using the formula: Output Power = Efficiency * Input Power. Here, Output Power = 0.8 * 500 W = 400 W.

In a hydraulic lift, if the input power is 500 W and the efficiency is 80%, what is the output power?

In a hydraulic lift, if the input power is 500 W and the efficiency is 80%, what is the output power?

Step 1: Understand the terms. Input power is the power you put into the lift, which is 500 W.
Step 2: Know the efficiency. Efficiency is how well the lift uses the input power, given as 80%, or 0.8 in decimal form.
Step 3: Use the formula for output power. The formula is: Output Power = Efficiency * Input Power.
Step 4: Plug in the numbers. Replace Efficiency with 0.8 and Input Power with 500 W in the formula.
Step 5: Calculate the output power. Multiply 0.8 by 500 W to get 400 W.

Efficiency in Power Systems – Understanding how efficiency affects the relationship between input and output power in systems like hydraulic lifts.