A 2 kg object is dropped from a height of 20 m. What is its potential energy at
Practice Questions
Q1
A 2 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 9.8 m/s²)
39.2 J
196 J
78.4 J
98.0 J
Questions & Step-by-Step Solutions
A 2 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 9.8 m/s²)
Step 1: Identify the mass of the object. In this case, the mass (m) is 2 kg.
Step 2: Identify the height from which the object is dropped. Here, the height (h) is 20 m.
Step 3: Identify the acceleration due to gravity. It is given as g = 9.8 m/s².
Step 4: Use the formula for potential energy (PE), which is PE = m × g × h.
Step 5: Substitute the values into the formula: PE = 2 kg × 9.8 m/s² × 20 m.
Step 6: Calculate the potential energy: 2 × 9.8 × 20 = 392 J.
Potential Energy – Potential energy is the energy stored in an object due to its position in a gravitational field, calculated using the formula PE = m × g × h.
Units of Measurement – Understanding the units involved in the calculation, such as kilograms for mass, meters for height, and joules for energy.