A lens forms a virtual image at a distance of 12 cm when the object is placed at

Practice Questions

Q1
A lens forms a virtual image at a distance of 12 cm when the object is placed at 8 cm. What is the focal length of the lens?
  1. 4 cm
  2. 6 cm
  3. 8 cm
  4. 10 cm

Questions & Step-by-Step Solutions

A lens forms a virtual image at a distance of 12 cm when the object is placed at 8 cm. What is the focal length of the lens?
  • Step 1: Identify the given values. The object distance (u) is -8 cm (negative because it is on the same side as the object) and the image distance (v) is 12 cm (positive because it is a virtual image).
  • Step 2: Write down the lens formula: 1/f = 1/v - 1/u.
  • Step 3: Substitute the values into the lens formula: 1/f = 1/12 - 1/(-8).
  • Step 4: Calculate 1/12, which is 0.0833, and 1/(-8), which is -0.125. So, 1/f = 0.0833 + 0.125.
  • Step 5: Add the two fractions: 1/f = 0.0833 + 0.125 = 0.2083.
  • Step 6: To find f, take the reciprocal of 0.2083: f = 1/0.2083.
  • Step 7: Calculate f, which is approximately 4 cm.
  • Lens Formula – The lens formula relates the focal length (f), the object distance (u), and the image distance (v) using the equation 1/f = 1/v - 1/u.
  • Virtual Image Formation – A virtual image is formed when the light rays diverge, and it appears on the same side of the lens as the object.
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