A block of mass 10 kg is resting on a horizontal surface. If the coefficient of

Practice Questions

Q1
A block of mass 10 kg is resting on a horizontal surface. If the coefficient of static friction is 0.5, what is the maximum static frictional force acting on the block?
  1. 25 N
  2. 50 N
  3. 75 N
  4. 100 N

Questions & Step-by-Step Solutions

A block of mass 10 kg is resting on a horizontal surface. If the coefficient of static friction is 0.5, what is the maximum static frictional force acting on the block?
Correct Answer: 50 N
  • Step 1: Identify the mass of the block. The mass is given as 10 kg.
  • Step 2: Identify the coefficient of static friction (μs). It is given as 0.5.
  • Step 3: Calculate the weight of the block (N), which is the force due to gravity. Use the formula: N = mass * gravity. Here, gravity (g) is approximately 9.8 m/s².
  • Step 4: Calculate the weight: N = 10 kg * 9.8 m/s² = 98 N.
  • Step 5: Use the formula for maximum static frictional force (Fs): Fs = μs * N.
  • Step 6: Substitute the values into the formula: Fs = 0.5 * 98 N.
  • Step 7: Calculate the maximum static frictional force: Fs = 49 N.
  • Step 8: Round the answer if necessary. The maximum static frictional force is approximately 50 N.
  • Static Friction – The force that resists the initiation of sliding motion between two surfaces in contact.
  • Normal Force – The perpendicular force exerted by a surface on an object resting on it, equal to the weight of the object in this case.
  • Coefficient of Static Friction – A dimensionless value that represents the ratio of the maximum static frictional force to the normal force.
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