A stone is thrown vertically upward with a speed of 20 m/s. How high will it ris

A stone is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?

A stone is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?

Step 1: Identify the initial speed (u) of the stone, which is given as 20 m/s.
Step 2: Identify the acceleration due to gravity (g), which is approximately 9.8 m/s².
Step 3: Use the formula for maximum height (H) when an object is thrown upwards: H = (u²) / (2g).
Step 4: Substitute the values into the formula: H = (20 m/s)² / (2 * 9.8 m/s²).
Step 5: Calculate (20 m/s)², which equals 400 m²/s².
Step 6: Calculate 2 * 9.8 m/s², which equals 19.6 m/s².
Step 7: Divide 400 m²/s² by 19.6 m/s² to find H: H ≈ 20.4 m.
Step 8: Conclude that the maximum height the stone will rise before coming to rest is approximately 20.4 meters.

Kinematics – The study of motion, specifically how objects move under the influence of forces, including the equations of motion for objects in free fall.
Projectile Motion – The motion of an object thrown into the air, which is influenced by gravity, and involves calculating maximum height, time of flight, and range.
Energy Conservation – The principle that energy cannot be created or destroyed, only transformed, which applies to the conversion of kinetic energy to potential energy at the maximum height.