A projectile is launched with an initial velocity of 30 m/s at an angle of 60 de

A projectile is launched with an initial velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?

A projectile is launched with an initial velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?

Step 1: Identify the initial velocity (u) of the projectile, which is given as 30 m/s.
Step 2: Identify the angle (θ) at which the projectile is launched, which is given as 60 degrees.
Step 3: Use the formula to find the horizontal component of the velocity: u_x = u * cos(θ).
Step 4: Calculate cos(60 degrees). The value of cos(60 degrees) is 0.5.
Step 5: Substitute the values into the formula: u_x = 30 m/s * 0.5.
Step 6: Perform the multiplication: 30 * 0.5 = 15 m/s.
Step 7: Conclude that the horizontal component of the velocity is 15 m/s.

Projectile Motion – Understanding the components of velocity in projectile motion, specifically how to calculate the horizontal component using trigonometric functions.
Trigonometric Functions – Applying cosine to find the horizontal component of velocity based on the launch angle.