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A projectile is launched with an initial velocity of 30 m/s at an angle of 60 de

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Question: A projectile is launched with an initial velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?

Options:

  1. 15 m/s
  2. 20 m/s
  3. 25 m/s
  4. 30 m/s

Correct Answer: 20 m/s

Solution: 

Horizontal component (u_x) = u * cos(θ) = 30 * 0.5 = 15 m/s.

A projectile is launched with an initial velocity of 30 m/s at an angle of 60 de

Practice Questions

Q1
A projectile is launched with an initial velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?
  1. 15 m/s
  2. 20 m/s
  3. 25 m/s
  4. 30 m/s

Questions & Step-by-Step Solutions

A projectile is launched with an initial velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?
  • Step 1: Identify the initial velocity (u) of the projectile, which is given as 30 m/s.
  • Step 2: Identify the angle (θ) at which the projectile is launched, which is given as 60 degrees.
  • Step 3: Use the formula to find the horizontal component of the velocity: u_x = u * cos(θ).
  • Step 4: Calculate cos(60 degrees). The value of cos(60 degrees) is 0.5.
  • Step 5: Substitute the values into the formula: u_x = 30 m/s * 0.5.
  • Step 6: Perform the multiplication: 30 * 0.5 = 15 m/s.
  • Step 7: Conclude that the horizontal component of the velocity is 15 m/s.
  • Projectile Motion – Understanding the components of velocity in projectile motion, specifically how to calculate the horizontal component using trigonometric functions.
  • Trigonometric Functions – Applying cosine to find the horizontal component of velocity based on the launch angle.
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