If the radius of the Earth is R and a satellite is in a circular orbit at a heig

Practice Questions

Q1
If the radius of the Earth is R and a satellite is in a circular orbit at a height h above the Earth's surface, what is the expression for the orbital speed v of the satellite?
  1. v = sqrt(GM/(R+h))
  2. v = sqrt(GM/R)
  3. v = sqrt(GM/(R-h))
  4. v = sqrt(GM/(R^2 + h^2))

Questions & Step-by-Step Solutions

If the radius of the Earth is R and a satellite is in a circular orbit at a height h above the Earth's surface, what is the expression for the orbital speed v of the satellite?
  • Step 1: Understand that the radius of the Earth is R.
  • Step 2: Recognize that the satellite is at a height h above the Earth's surface.
  • Step 3: Realize that the total distance from the center of the Earth to the satellite is R + h.
  • Step 4: Recall that the gravitational force provides the necessary centripetal force for the satellite's circular orbit.
  • Step 5: Use the formula for gravitational force: F = GMm/(R+h)^2, where M is the mass of the Earth and m is the mass of the satellite.
  • Step 6: Set the gravitational force equal to the centripetal force: F = mv^2/(R+h).
  • Step 7: Cancel the mass of the satellite (m) from both sides of the equation.
  • Step 8: Rearrange the equation to solve for v: v^2 = GM/(R+h).
  • Step 9: Take the square root of both sides to find the orbital speed: v = sqrt(GM/(R+h)).
  • Gravitational Forces – Understanding how gravitational forces act on objects in orbit and the relationship between mass, distance, and gravitational acceleration.
  • Orbital Mechanics – Knowledge of the principles governing the motion of satellites and the derivation of formulas related to orbital speed.
  • Circular Motion – Application of circular motion principles to derive the speed of an object in a circular path.
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