Question: If the electric potential at point A is 5 V and at point B is 15 V, what is the work done by the electric field in moving a charge of 2 C from A to B?
Options:
Correct Answer: -20 J
Solution:
Work done W = Q(V_B - V_A) = 2 C * (15 V - 5 V) = 20 J.