A capacitor is charged to a potential difference of 12 V. If the capacitance is
Practice Questions
Q1
A capacitor is charged to a potential difference of 12 V. If the capacitance is 4 µF, what is the charge stored in the capacitor?
12 µC
24 µC
48 µC
36 µC
Questions & Step-by-Step Solutions
A capacitor is charged to a potential difference of 12 V. If the capacitance is 4 µF, what is the charge stored in the capacitor?
Step 1: Understand the formula for charge stored in a capacitor, which is Q = C * V.
Step 2: Identify the values given in the question: capacitance (C) is 4 µF and potential difference (V) is 12 V.
Step 3: Convert the capacitance from microfarads (µF) to farads (F) if necessary. 4 µF = 4 x 10^-6 F.
Step 4: Substitute the values into the formula: Q = (4 x 10^-6 F) * (12 V).
Step 5: Calculate the charge: Q = 48 x 10^-6 C.
Step 6: Convert the charge back to microcoulombs (µC) if needed: 48 x 10^-6 C = 48 µC.
Capacitance and Charge Relationship – This concept involves understanding the relationship between charge (Q), capacitance (C), and voltage (V) in a capacitor, expressed by the formula Q = CV.
