If a 60W light bulb operates at 120V, what is the resistance of the bulb?

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Question: If a 60W light bulb operates at 120V, what is the resistance of the bulb?

Options:

Correct Answer: 120 ohms

Solution:

Power (P) = V^2 / R, so R = V^2 / P = (120V)^2 / 60W = 240 ohms.

If a 60W light bulb operates at 120V, what is the resistance of the bulb?

If a 60W light bulb operates at 120V, what is the resistance of the bulb?

Step 1: Identify the power (P) of the light bulb, which is 60 watts.
Step 2: Identify the voltage (V) at which the light bulb operates, which is 120 volts.
Step 3: Use the formula for power, which is P = V^2 / R, where R is the resistance.
Step 4: Rearrange the formula to solve for resistance (R): R = V^2 / P.
Step 5: Substitute the values into the formula: R = (120V)^2 / 60W.
Step 6: Calculate (120V)^2, which equals 14400.
Step 7: Divide 14400 by 60 to find R: R = 14400 / 60.
Step 8: Calculate the result, which is 240 ohms.

Ohm's Law and Power Formula – Understanding the relationship between power, voltage, and resistance in electrical circuits.