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In a circuit with two resistors in parallel, if one resistor is 6Ω and the other

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Question: In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current if a voltage of 12V is applied across the combination?

Options:

  1. 2A
  2. 4A
  3. 6A
  4. 8A

Correct Answer: 4A

Solution: 

Total resistance in parallel: 1/Rtotal = 1/6 + 1/3 = 1/2. Rtotal = 2Ω. Total current I = V/R = 12V/2Ω = 6A.

In a circuit with two resistors in parallel, if one resistor is 6Ω and the other

Practice Questions

Q1
In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current if a voltage of 12V is applied across the combination?
  1. 2A
  2. 4A
  3. 6A
  4. 8A

Questions & Step-by-Step Solutions

In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current if a voltage of 12V is applied across the combination?
  • Step 1: Identify the resistors in the circuit. We have one resistor of 6Ω and another of 3Ω.
  • Step 2: Use the formula for total resistance in parallel: 1/Rtotal = 1/R1 + 1/R2.
  • Step 3: Substitute the values into the formula: 1/Rtotal = 1/6 + 1/3.
  • Step 4: Find a common denominator to add the fractions. The common denominator for 6 and 3 is 6.
  • Step 5: Rewrite 1/3 as 2/6, so now we have: 1/Rtotal = 1/6 + 2/6.
  • Step 6: Add the fractions: 1/Rtotal = 3/6.
  • Step 7: Simplify the fraction: 1/Rtotal = 1/2.
  • Step 8: Invert the fraction to find Rtotal: Rtotal = 2Ω.
  • Step 9: Use Ohm's Law to find the total current: I = V/R.
  • Step 10: Substitute the values: I = 12V / 2Ω.
  • Step 11: Calculate the total current: I = 6A.
  • Parallel Resistors – Understanding how to calculate total resistance in a parallel circuit and applying Ohm's Law to find total current.
  • Ohm's Law – Using the relationship between voltage, current, and resistance to solve for current in a circuit.
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