What are the solutions of the equation sin^2(x) - sin(x) = 0?

Practice Questions

Q1
What are the solutions of the equation sin^2(x) - sin(x) = 0?
  1. x = nπ
  2. x = nπ + π/2
  3. x = nπ + 2π
  4. x = nπ + π

Questions & Step-by-Step Solutions

What are the solutions of the equation sin^2(x) - sin(x) = 0?
  • Step 1: Start with the equation sin^2(x) - sin(x) = 0.
  • Step 2: Notice that this equation can be factored. Rewrite it as sin(x)(sin(x) - 1) = 0.
  • Step 3: Set each factor equal to zero. First, set sin(x) = 0.
  • Step 4: Solve sin(x) = 0. The solutions are x = nπ, where n is any integer.
  • Step 5: Now, set the second factor equal to zero: sin(x) - 1 = 0.
  • Step 6: Solve sin(x) - 1 = 0. This gives sin(x) = 1.
  • Step 7: The solutions for sin(x) = 1 are x = π/2 + 2nπ, where n is any integer.
  • Step 8: Combine the solutions from both factors. The final solutions are x = nπ or x = π/2 + 2nπ.
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