Question: In triangle ABC, if angle A = 45 degrees and side a = 10 cm, what is the length of side b if angle B = 60 degrees?
Options:
Correct Answer: 8.66 cm
Solution:
Using the Law of Sines: a/sin(A) = b/sin(B). Therefore, b = a * (sin(B)/sin(A)) = 10 * (sin(60)/sin(45)) = 10 * (β3/2)/(β2/2) = 10 * β3/β2 = 10 * β(3/2) = 8.66 cm.