Question: A man is standing on the ground and observes the top of a building at an angle of elevation of 60 degrees. If he is 50 m away from the building, what is the height of the building?
Options:
Correct Answer: 43.3 m
Solution:
Using tan(60Β°) = height/50, we have β3 = height/50. Therefore, height = 50β3 β 86.6 m.