A box contains 5 white and 3 black balls. If one ball is drawn at random, what i

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Question: A box contains 5 white and 3 black balls. If one ball is drawn at random, what is the probability that it is not black?

Options:

Correct Answer: 5/8

Solution:

The probability of not drawing a black ball is the probability of drawing a white ball, which is 5/8.

A box contains 5 white and 3 black balls. If one ball is drawn at random, what is the probability that it is not black?

A box contains 5 white and 3 black balls. If one ball is drawn at random, what is the probability that it is not black?

Correct Answer: 5/8

Step 1: Count the total number of balls in the box. There are 5 white balls and 3 black balls.
Step 2: Add the number of white balls and black balls together. Total = 5 + 3 = 8 balls.
Step 3: Identify the number of balls that are not black. Since there are 5 white balls, the number of balls that are not black is 5.
Step 4: Calculate the probability of drawing a ball that is not black. This is done by dividing the number of non-black balls (5) by the total number of balls (8).
Step 5: Write the probability as a fraction: Probability = 5/8.

Probability – The likelihood of an event occurring, calculated as the number of favorable outcomes divided by the total number of possible outcomes.
Complementary Events – Events that cover all possible outcomes; in this case, drawing a ball that is not black includes drawing a white ball.