A box contains 5 red, 3 green, and 2 blue marbles. If a marble is drawn at rando

Practice Questions

Q1
A box contains 5 red, 3 green, and 2 blue marbles. If a marble is drawn at random, what is the probability that it is green given that it is not red?
  1. 1/2
  2. 1/3
  3. 1/4
  4. 1/5

Questions & Step-by-Step Solutions

A box contains 5 red, 3 green, and 2 blue marbles. If a marble is drawn at random, what is the probability that it is green given that it is not red?
  • Step 1: Count the total number of marbles in the box. There are 5 red, 3 green, and 2 blue marbles.
  • Step 2: Calculate the total number of marbles: 5 (red) + 3 (green) + 2 (blue) = 10 marbles.
  • Step 3: Identify the non-red marbles. These are the green and blue marbles.
  • Step 4: Count the non-red marbles: 3 (green) + 2 (blue) = 5 non-red marbles.
  • Step 5: Determine how many of the non-red marbles are green. There are 3 green marbles.
  • Step 6: Calculate the probability of drawing a green marble given that it is not red. This is the number of green marbles divided by the total number of non-red marbles: 3 (green) / 5 (non-red) = 3/5.
  • Conditional Probability – The probability of an event occurring given that another event has already occurred.
  • Total Probability – Understanding how to calculate the total number of favorable outcomes versus the total number of possible outcomes.
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