Determine the value of p for which the function f(x) = { 2x + 3, x < 2; px +
Practice Questions
Q1
Determine the value of p for which the function f(x) = { 2x + 3, x < 2; px + 1, x = 2; x^2 - 1, x > 2 is continuous at x = 2.
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Questions & Step-by-Step Solutions
Determine the value of p for which the function f(x) = { 2x + 3, x < 2; px + 1, x = 2; x^2 - 1, x > 2 is continuous at x = 2.
Step 1: Identify the function f(x) which is defined in three parts based on the value of x.
Step 2: Recognize that we need to check the continuity of f(x) at x = 2.
Step 3: For continuity at x = 2, the left-hand limit (as x approaches 2 from the left) must equal the value of the function at x = 2, which must also equal the right-hand limit (as x approaches 2 from the right).
Step 4: Calculate the left-hand limit: f(2) from the left is given by the first part of the function, so we calculate 2(2) + 3.
Step 6: The value of the function at x = 2 is given by the second part of the function, which is px + 1. So, we substitute x = 2: f(2) = p(2) + 1 = 2p + 1.
Step 7: Calculate the right-hand limit: f(2) from the right is given by the third part of the function, so we calculate (2)^2 - 1.