What is the standard entropy change (ΔS°) for the reaction: 2 SO2(g) + O2(g) → 2

₹0.0

Question: What is the standard entropy change (ΔS°) for the reaction: 2 SO2(g) + O2(g) → 2 SO3(g)?

Options:

Correct Answer: Negative

Solution:

The reaction decreases the number of gas molecules from 3 to 2, leading to a decrease in disorder and thus a negative ΔS°.

What is the standard entropy change (ΔS°) for the reaction: 2 SO2(g) + O2(g) → 2 SO3(g)?

What is the standard entropy change (ΔS°) for the reaction: 2 SO2(g) + O2(g) → 2 SO3(g)?

Step 1: Identify the reactants and products in the reaction: 2 SO2(g) + O2(g) → 2 SO3(g).
Step 2: Count the number of gas molecules on the reactant side: 2 SO2 + 1 O2 = 3 gas molecules.
Step 3: Count the number of gas molecules on the product side: 2 SO3 = 2 gas molecules.
Step 4: Compare the number of gas molecules: The reactants have 3 gas molecules and the products have 2 gas molecules.
Step 5: Understand that a decrease in the number of gas molecules means a decrease in disorder (or randomness).
Step 6: Conclude that since the disorder decreases, the standard entropy change (ΔS°) is negative.

No concepts available.