In the reaction 2Fe^3+ + 2I^- → 2Fe^2+ + I2, which species is the reducing agent

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Question: In the reaction 2Fe^3+ + 2I^- → 2Fe^2+ + I2, which species is the reducing agent?

Options:

Correct Answer: I^-

Solution:

I^- donates electrons to Fe^3+, thus it is the reducing agent.

In the reaction 2Fe^3+ + 2I^- → 2Fe^2+ + I2, which species is the reducing agent?

In the reaction 2Fe^3+ + 2I^- → 2Fe^2+ + I2, which species is the reducing agent?

Step 1: Identify the reactants in the reaction: 2Fe^3+ and 2I^-.
Step 2: Understand what a reducing agent does: it donates electrons to another species.
Step 3: Look at the oxidation states: Fe^3+ is reduced to Fe^2+, meaning it gains electrons.
Step 4: Notice that I^- is changing to I2, which means it is losing electrons.
Step 5: Since I^- donates electrons to Fe^3+, it is the one that reduces Fe^3+.
Step 6: Conclude that I^- is the reducing agent because it donates electrons.

Redox Reactions – Understanding oxidation and reduction processes, where the reducing agent donates electrons and is oxidized.
Oxidation States – Identifying changes in oxidation states to determine which species is oxidized and which is reduced.