What is the percentage composition of carbon in glucose (C6H12O6)?

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Q: What is the percentage composition of carbon in glucose (C6H12O6)?

Solution: Molar mass of glucose = 6(12) + 12(1) + 6(16) = 180 g. Percentage of carbon = (72/180) x 100 = 40%.

Steps: 9

Step 1: Identify the chemical formula of glucose, which is C6H12O6.
Step 2: Calculate the molar mass of glucose by adding the masses of all the atoms in the formula.
Step 3: For carbon (C), there are 6 atoms. The molar mass of carbon is approximately 12 g/mol. So, 6 x 12 = 72 g.
Step 4: For hydrogen (H), there are 12 atoms. The molar mass of hydrogen is approximately 1 g/mol. So, 12 x 1 = 12 g.
Step 5: For oxygen (O), there are 6 atoms. The molar mass of oxygen is approximately 16 g/mol. So, 6 x 16 = 96 g.
Step 6: Add the total masses together: 72 g (C) + 12 g (H) + 96 g (O) = 180 g. This is the molar mass of glucose.
Step 7: To find the percentage composition of carbon, use the formula: (mass of carbon / molar mass of glucose) x 100.
Step 8: Substitute the values: (72 g / 180 g) x 100 = 40%.
Step 9: Conclude that the percentage composition of carbon in glucose is 40%.