What type of hybridization occurs in the complex ion [Fe(CN)6]3-?

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Q: What type of hybridization occurs in the complex ion [Fe(CN)6]3-?

Solution: [Fe(CN)6]3- exhibits d2sp3 hybridization due to the octahedral arrangement of ligands.

Steps: 7

Step 1: Identify the central metal ion in the complex ion [Fe(CN)6]3-. The central metal ion is Iron (Fe).
Step 2: Determine the oxidation state of Iron in the complex. Since CN- is a -1 charge and there are 6 CN- ligands, the total negative charge is -6. The overall charge of the complex is -3, so the oxidation state of Fe is +3.
Step 3: Write the electron configuration of Fe in the +3 oxidation state. The electron configuration of neutral Fe is [Ar] 4s2 3d6. For Fe3+, we remove 3 electrons, resulting in [Ar] 3d5.
Step 4: Identify the type of ligands. CN- is a strong field ligand, which means it can cause pairing of electrons in the d-orbitals.
Step 5: Determine the arrangement of the ligands around the central metal ion. Since there are 6 CN- ligands, they will arrange themselves in an octahedral geometry.
Step 6: Understand the hybridization that occurs in an octahedral complex. In an octahedral arrangement, the hybridization involves one s orbital, three p orbitals, and two d orbitals.
Step 7: Conclude the hybridization type. The hybridization for [Fe(CN)6]3- is d2sp3, which corresponds to the use of two d orbitals, one s orbital, and three p orbitals.