What is the enthalpy change for the reaction: N2(g) + 3H2(g) → 2NH3(g) if the st

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Question: What is the enthalpy change for the reaction: N2(g) + 3H2(g) → 2NH3(g) if the standard enthalpy of formation of NH3(g) is -45.9 kJ/mol?

Options:

Correct Answer: -91.8 kJ

Solution:

The enthalpy change for the reaction is 2 times the standard enthalpy of formation of NH3(g), which is -45.9 kJ/mol, giving -91.8 kJ.

What is the enthalpy change for the reaction: N2(g) + 3H2(g) → 2NH3(g) if the standard enthalpy of formation of NH3(g) is -45.9 kJ/mol?

What is the enthalpy change for the reaction: N2(g) + 3H2(g) → 2NH3(g) if the standard enthalpy of formation of NH3(g) is -45.9 kJ/mol?

Step 1: Identify the reaction: N2(g) + 3H2(g) → 2NH3(g).
Step 2: Understand that the standard enthalpy of formation of NH3(g) is given as -45.9 kJ/mol.
Step 3: Note that the reaction produces 2 moles of NH3(g).
Step 4: Calculate the total enthalpy change by multiplying the standard enthalpy of formation of NH3(g) by the number of moles produced: 2 moles × -45.9 kJ/mol.
Step 5: Perform the multiplication: 2 × -45.9 = -91.8 kJ.
Step 6: Conclude that the enthalpy change for the reaction is -91.8 kJ.

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