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What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l)

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Question: What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l) if the standard enthalpy of formation of H2O(l) is -285.8 kJ/mol?

Options:

  1. -285.8 kJ/mol
  2. 285.8 kJ/mol
  3. 0 kJ/mol
  4. 571.6 kJ/mol

Correct Answer: -285.8 kJ/mol

Solution:

The change in enthalpy for the reaction is equal to the standard enthalpy of formation of H2O(l), which is -285.8 kJ/mol.

What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l)

Practice Questions

Q1
What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l) if the standard enthalpy of formation of H2O(l) is -285.8 kJ/mol?
  1. -285.8 kJ/mol
  2. 285.8 kJ/mol
  3. 0 kJ/mol
  4. 571.6 kJ/mol

Questions & Step-by-Step Solutions

What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l) if the standard enthalpy of formation of H2O(l) is -285.8 kJ/mol?
  • Step 1: Identify the reaction: H2(g) + 1/2 O2(g) → H2O(l).
  • Step 2: Understand that the standard enthalpy of formation (ΔHf) is the change in enthalpy when one mole of a compound is formed from its elements in their standard states.
  • Step 3: Note that the standard enthalpy of formation of H2O(l) is given as -285.8 kJ/mol.
  • Step 4: Recognize that the change in enthalpy (ΔH) for the reaction is equal to the standard enthalpy of formation of the product, H2O(l).
  • Step 5: Conclude that the change in enthalpy (ΔH) for the reaction is -285.8 kJ/mol.
  • Enthalpy of Formation – The standard enthalpy of formation is the change in enthalpy when one mole of a compound is formed from its elements in their standard states.
  • Reaction Enthalpy – The change in enthalpy (ΔH) for a reaction can be determined using the standard enthalpy of formation values of the reactants and products.
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