Calculate the change in enthalpy (ΔH) when 2 moles of a substance absorb 500 J o
Practice Questions
Q1
Calculate the change in enthalpy (ΔH) when 2 moles of a substance absorb 500 J of heat at constant pressure.
250 J/mol
500 J/mol
1000 J/mol
125 J/mol
Questions & Step-by-Step Solutions
Calculate the change in enthalpy (ΔH) when 2 moles of a substance absorb 500 J of heat at constant pressure.
Step 1: Understand that enthalpy change (ΔH) is calculated using the formula ΔH = q/n, where q is the heat absorbed and n is the number of moles.
Step 2: Identify the values given in the question: q = 500 J (heat absorbed) and n = 2 mol (number of moles).
Step 3: Substitute the values into the formula: ΔH = 500 J / 2 mol.
Step 4: Perform the division: 500 J divided by 2 mol equals 250 J/mol.
Step 5: Conclude that the change in enthalpy (ΔH) is 250 J/mol.
Enthalpy Change – The change in enthalpy (ΔH) is the heat absorbed or released by a system at constant pressure, calculated per mole of substance.
Heat Transfer – Understanding the relationship between heat (q), number of moles (n), and enthalpy change (ΔH) is crucial for thermodynamic calculations.
Molar Calculations – Calculating ΔH requires dividing the total heat absorbed by the number of moles to find the enthalpy change per mole.
